John has 'x' children by his first wife and Anglina has 'x + 1' children by her first husband. They both marry and have their own children. The whole family has 24 children. It is given that the children of the same parents don't fight. Then find then maximum number of fights that can take place in the family.
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
Let No. of children of john & anglina = y
∴ x + (x + 1) + y = 24
y = 23 – 2x
Number of fights
F = x(x + 1) + x(23 – 2x) + (x + 1) (23 – 2x)
F = – 3x 2 + 45x + 23
= 0 ⇒ – 6x + 45 = 0 ⇒ x = 7.5
But 'x' wil be integral.
check x = 6 or x = 7
F = 191
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